y^2-15y+52=0

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Solution for y^2-15y+52=0 equation: 



y^2-15y+52=0

a = 1; b = -15; c = +52;
Δ = b2-4ac
Δ = -152-4·1·52
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{17}}{2*1}=\frac{15-\sqrt{17}}{2}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{17}}{2*1}=\frac{15+\sqrt{17}}{2}
$

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